[PyQt] wrap QApplication::exec() into a function or class

[Zhao Lee]

I want the following code to get the request url starting with http://down.51en.com:88 during the web loading process , 
code here
https://bpaste.net/show/120af9114a8e


once targetUrl is assigned a value , I want the function targetUrlGetter(url) to return it to the caller, however , the problem is that QApplication::exec() hanged the program , so the function cannot return , I have tried with qApp.quit() in interceptRequest(self, info) in order to tell the application to exit so that targetUrlGetter(url) can return , but the function still cannot return and the program even crashes on exit(tested on win7 32bit), so how can I return the targetUrl to the caller program ?

BTW, I am going to use the code at (Django) web server side.








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