[PyQt] New style signal connect not working

[Tony Arnold]

Alan,

On 05/02/15 19:45, Alan Ezust wrote:
> Perhaps adding a @pyqtSlot(QModelIndex,QModelIndex) above the function
> def will help?

Thanks. Exactly what I needed. Now works perfectly!

> On Thu, Feb 5, 2015 at 11:16 AM, Tony Arnold
> <tony.arnold at manchester.ac.uk <mailto:tony.arnold at manchester.ac.uk>> wrote:
> 
>     I have an application with a QTableView and I am trying to connect the
>     currentRowChanged signal to a slot. When I use the old style, it works,
>     but the newer style does not.
> 
>     Here is the code to connect the signal using the old style:
> 
>     self.connect(self.competitionView.selectionModel(),
>                       SIGNAL("currentRowChanged(QModelIndex,QModelIndex)"),
>                         self.competitionChanged)
> 
>     and the slot is defined as:
> 
>         def competitionChanged(self, index):
> 
>     This works fine.
> 
>     But if I connect the signal with the preferred new style so:
> 
>     self.competitionView.selectionModel().currentRowChanged.connect(self.competitionChanged)
> 
>     Then an exception gets raised when the slot gets called. I get the
>     following error:
> 
>     The debugged program raised the exception unhandled TypeError
>     "competitionChanged() missing 1 required positional argument: 'index'"
> 
>     I am using PyQt4 and python 3.4 with Qt 4.8.6
> 
>     Any suggestions where I might be going wrong?


Regards,
Tony.
-- 
Tony Arnold, IT Security Analyst, University of Manchester.
T: +44 (0) 161 275 6093, F: +44 (0) 705 344 3082,
M: +44 (0) 773 330 0039, E: tony.arnold at manchester.ac.uk