[PyQt] using itemDoubleClicked with pyqt

[Christopher M. Nahler]

On 23.06.2010 09:46, Phil Thompson wrote:
>  On Wed, 23 Jun 2010 09:40:09 +0200, "Christopher M. Nahler"
>  <christopher.nahler at papermodels.at>   wrote:
>
>>  I have problems using a signal. In the code below I create a QListWidget
>>  where I would like to act upon doubleClicking an item.
>>
>>  In the documentation I have found the signal "itemDoubleClicked".
>>  (http://doc.qt.nokia.com/4.6/qlistwidget.html#itemDoubleClicked)
>>  But somehow I am not using it right. What am I doing wrong?
>>
>>  thanks in advance
>>  Chris
>>
>>
>>
>>  import sys
>>  from PyQt4.QtCore import *
>>  from PyQt4.QtGui import *
>>
>>  itemList = ["One",
>>                 "Two",
>>                 "Three",
>>                 "Four",
>>                 "Five"]
>>
>>  class ListDlg(QDialog):
>>
>>        def __init__(self, name, parent=None):
>>            super(ListDlg, self).__init__(parent)
>>
>>            self.myList = QListWidget()
>>            self.myList.addItems(itemList)
>>            self.myList.setCurrentRow(0)
>>
>>            layout = QHBoxLayout()
>>            layout.addWidget(self.myList)
>>            self.setLayout(layout)
>>            self.connect(self.myList, SIGNAL("itemDoubleClicked(*item)"),
>>  self.processItem)
>>
>>        def processItem(self, item):
>>            print(item.text())
>>
>>  if __name__ == "__main__":
>>        app = QApplication(sys.argv)
>>        form = ListDlg("Listdialog")
>>        form.exec_()
>>
>  The signal signature is "itemDoubleClicked(QListWidgetItem *)"
>
>  Phil
>
The way I understand this is that the signal passes a pointer to an
item, right? So what is the correct way to setup the connection? I have
tried with SIGNAL("itemDoubleClicked(item*)" and
SIGNAL("itemDoubleClicked(item *)" but that also did not work.