[PyQt] Re: Wait Dialog and pyserial

[Ruslan Popov]

The answer is:
Just read carefully about QEvent and QCoreApplication.postEvent and you've
know that there is no need to use QWaitCondition at all in this case.

On Tue, Dec 1, 2009 at 10:15 PM, Ruslan Popov <ruslan.popov at gmail.com>wrote:

> Hi, all.
>
> I am working on a part of application, the app needs to read RFID id from
> label, RFID reader is accessible via COM port (I've used pyserial for that).
>
> I have tried to do so:
>
> [main code]
> class MainWindow(QMainWindow):
>
>     def __init__(self, parent=None):
>         QMainWindow.__init__(self, parent)
>
>         self.rfidReader = QWaitCondition()
>         self.rfidWaiter = QWaitCondition()
>         self.rfidMutex = QMutex()
>         self.callback = self.readedRFID
>         self.reader = WaitingRFID(self)
>         self.reader.start()
>
> ..
>
>     def waitingRFID(self):
>         self.rfidReader.wakeAll()
>
>         self.dlg = DlgWaitingRFID()
>         self.dlg.setModal(True)
>         self.dlg.exec_()
>
>         #self.rfidMutex.lock()
>         #self.rfidWaiter.wait(self.rfidMutex)
>         #self.rfidMutex.unlock()
>
>     def readedRFID(self, rfid):
>         self.rfid_id = rfid
>         print 'readedRFID:', rfid
>         #self.rfidWaiter.wakeAll()
>         self.dlg.close()
>
> [Thread code]
> class WaitingRFID(QThread):
>     def __init__(self, parent):
>         self.callback = parent.callback
>         self.mutex = parent.rfidMutex
>         self.condition = parent.rfidReader
>         QThread.__init__(self)
>
>     def hex(self, symbol):
>         return '%02X' % ord(symbol)
>
>     def run(self):
>         while True:
>             port = serial.Serial(PORT['name'], PORT['rate'],
>                                  bytesize = PORT['bits_in_byte'],
>                                  parity = PORT['parity'],
>                                  stopbits = PORT['stop_bits']
>                                  )
>             port.setDTR(True)
>             port.setRTS(True)
>
>             self.mutex.lock()
>             self.condition.wait(self.mutex)
>
>             buffer = []
>             while True:
>                 symbol = port.read(1)
>                 if not self.hex(symbol) == '0D':
>                     buffer.append(symbol)
>                 else:
>                     if '0A' == self.hex(port.read(1)):
>                         if len(buffer) == 9:
>                             rfid_code = ''.join(buffer[1:]) # see
> manager.py
>                             break
>                         buffer = []
>
>             self.callback(rfid_code)
>             self.mutex.unlock()
>
>             port.close()
>
> Thread code works well. The problem is in showing dialog.
> I need to show dialog with a label 'Put RFID label on the reader.' and run
> thread's loop. The loop reads RFID id and use callback function. At this
> point I need to close the dialog window. Tell me the right way to do it.
>
> Any help appreciated,
> --
> Ruslan Popov
> phone: +7 916 926 1205
>
>


-- 
Ruslan Popov
phone: +7 916 926 1205
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