[PyQt] thread in pyqt ... simple example needed

[massimo di stefano]

  .. done little step ahead :


import sys
from PyQt4 import QtCore, QtGui
import time

class MyThread(QtCore.QThread):
     def run(self):
		n = 0
		step = 1
		while True:
			n += step
			print n


class Gui(QtGui.QWidget):
     def __init__(self, parent=None):
         QtGui.QGroupBox.__init__(self, parent)
         self.gcenter = QtGui.QPushButton("X", self)
         self.gcenter.setAutoRepeat(True)
         guiLayout = QtGui.QGridLayout()
         guiLayout.addWidget(self.gcenter,1,0)
         self.setLayout(guiLayout)
         self.thread = MyThread()
         self.connect(self.gcenter, QtCore.SIGNAL("clicked()"),  
self.thread.start)



if __name__ == "__main__":
	app = QtGui.QApplication(sys.argv)
	gui = Gui()
	gui.show()
	sys.exit(app.exec_())



now i need to stop it when i "release" the button,
tried with :

         self.connect(self.gcenter, QtCore.SIGNAL("released()"),  
self.thread.quit)

but give :

AttributeError: stop

Il giorno 05/apr/09, alle ore 19:56, massimo di stefano ha scritto:

>
> Hi All,
>
> i'm doing my first experience using pyqt and tring to learn more  
> about it
> unlucky i'm not able to solve some problems by myself :-(
> i googled a lot about and i tried to use QTassistant
> ....
> but i'm pretty new to programming and i've some difficoult to learn.
>
> i tried to resume my problem in a sample script, that is :
>
>
> import sys
> from PyQt4 import QtCore, QtGui
> import time
>
> class Gui(QtGui.QWidget):
> 	def __init__(self, parent=None):
> 		QtGui.QGroupBox.__init__(self, parent)
> 		self.gcenter = QtGui.QPushButton("X", self)
> 		self.gcenter.setAutoRepeat(True)
> 		self.connect(self.gcenter, QtCore.SIGNAL("clicked()"),self.count)
> 		guiLayout = QtGui.QGridLayout()
> 		guiLayout.addWidget(self.gcenter,1,0)
> 		self.setLayout(guiLayout)
>
>
> 	def count(self):
> 		n = 0
> 		step = 1
> 		while True:
> 			n += step
> 			print n
> 			time.sleep(0.5)
>
>
> if __name__ == "__main__":
> 	app = QtGui.QApplication(sys.argv)
> 	gui = Gui()
> 	gui.show()
> 	sys.exit(app.exec_())
>
>
>
> as you can see the gui do not exit from the "while" statment
> and it freeze ...
> i know, i need to learn more about QTrhead usage...
> an example on how to change the previouse code, will give me a great  
> help!
>
> thanks for help me !!!
>
>
>
>
>
> Massimo Di Stefano
> massimodisasha at yahoo.it
>
> epifanio on   irc.freenode.net  /join gfoss
>
>
>
>
>
>
>
> Chiacchiera con i tuoi amici in tempo reale!http://it.yahoo.com/mail_it/foot/*http://it.messenger.yahoo.com
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