[PyQt] multiple signal connect
daniel at keystonewood.com
Wed Aug 20 20:17:27 BST 2008
Ahh, sorry, that will have the same problem you had before. Here's a
button.__slot = slot
for button in [ ... ]:
QtCore.QObject.connect( ... , slotmaker(button))
Note: it might not be possible to keep a reference to the slot on the
button itself--not sure if attribute assignment is possible directly
on qt objects that are not subclassed in Python. If not just keep a
list of slots attached to 'self' (your class) or something like that.
On Aug 20, 2008, at 3:09 PM, Daniel Miller wrote:
> Try this:
> for button in [...]:
> def slot():
> button.__slot = slot # keep a reference so it doesn't get GC'd
> QtCore.QObject.connect(..., slot)
> ~ Daniel
> On Aug 20, 2008, at 11:17 AM, Ruben Fonseca wrote:
>> I'm having a problem developing my first Python Qt4 app and I thought
>> you could help me.
>> I have a bunch of buttons that I want to watch for the "clicked()"
>> Since the handling is the same for all buttons I decided to write
>> something like this
>> for button in [self.button_1, self.button_2, ..., self.button_0]:
>> QtCore.QObject.connect(button, QtCore.SIGNAL('clicked()'), lambda:
>> def button_clicked(self, number):
>> print "Received a signal from %s" % number.objectName()
>> However, every time I click on a button I got on the console
>> "Received a signal from button_0"
>> regardless the button I click... So I'm guessing something's wrong
>> my lambda function.
>> What's the best way of solving this particular problem in Python?
>> Thank you for you support
>> Ruben Fonseca
>> PyQt mailing list PyQt at riverbankcomputing.com
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