[PyKDE] QAccel automatically sends signal
david at boddie.org.uk
Fri Apr 15 02:02:48 BST 2005
On Thu, 14 Apr 2005 16:05:07, Alfred Young wrote:
> self.shortcutKey = QAccel(self)
> id = self.shortcutKey.insertItem(Qt.Key_Enter)
> self.shortcutKey.connectItem(id, self.defaultButton,
> However as soon as I invoke connectItem() it appears that the
> defaultButton's slot is activated. I've tried a number of ways to get
> around this but no luck.
When you write self.defaultButton.clicked() you are actually calling
that function there and then.
> Does anyone know what I may be doing wrong? Maybe I'm not understanding
> QAccel's abilities?
You need to pass the slot's name as a string:
self.shortcutKey.connectItem(id, self.defaultButton, SLOT("clicked()"))
Alternatively, since this is Python, you can also write
which is much nicer to read. :-)
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